It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probab

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1. Answer:

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   Let the event wherein 2 students having the same birthday be E

   Given, P(E) = 0.992

   We know,

   P(E)+P(not E) = 1

   Or, P(not E) = 1–0.992 = 0.008

   ∴ The probability that the 2 students have the same birthday is 0.008

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