In triangle OPQ, right angled at P, OP-7cm and OQ-PQ = lem determine the value of Sin 8 and Cos 0. About the author Josie

Step-by-step explanation: Answer In Δ OPQ, we have OQ 2 =OP 2 +PQ 2 ⇒(PQ+1) 2 =OP 2 +PQ 2 [∵OQ−PQ=1⇒OQ=1+PQ] ⇒PQ 2 +2PQ+1=OP 2 +PQ 2 ⇒2PQ+1=49 ⇒PQ=24cm ∴OQ−PQ=1cm ⇒OQ=(PQ+1)cm=25cm Now, sinQ= OQ OP = 25 7 and, cosQ= OQ PQ = 25 24 Reply

Step-by-step explanation:Answer

In Δ OPQ, we have

OQ

2

=OP

2

+PQ

2

⇒(PQ+1)

2

=OP

2

+PQ

2

[∵OQ−PQ=1⇒OQ=1+PQ]

⇒PQ

2

+2PQ+1=OP

2

+PQ

2

⇒2PQ+1=49

⇒PQ=24cm

∴OQ−PQ=1cm

⇒OQ=(PQ+1)cm=25cm

Now, sinQ=

OQ

OP

=

25

7

and, cosQ=

OQ

PQ

=

25

24