in triangle ABC &D and E are points on the sides AB and AC respectively if is equal to AD=1.5 cm is DB= 3cm and EC=2cmfind AE About the author Lyla

Answer: DE∣∣BC ⟹∠ADE=∠ABC Corresponding angles ∠AED=∠ACB Corresponding angles ∠A is common to both the triangles. ∴ΔADE∼ΔABC by AAA similarity ⟹ AD AB = AE AC AD AB −1= AE AC −1 AD BD = AE CE EC=1× 1.5 3 =2 cm Step-by-step explanation: Mark me as brainlist Reply

Step-by-step explanation: The given information is shown in the attached diagram. DE∣∣BC ⟹∠ADE=∠ABC Corresponding angles ∠AED=∠ACB Corresponding angles ∠A is common to both the triangles. ∴ΔADE∼ΔABC by AAA similarity ⟹ AD AB = AE AC AD AB −1= AE AC −1 AD BD = AE CE EC=1× 1.5 3 =2 cm Reply

Answer:DE∣∣BC

⟹∠ADE=∠ABC Corresponding angles

∠AED=∠ACB Corresponding angles

∠A is common to both the triangles.

∴ΔADE∼ΔABC by AAA similarity

⟹

AD

AB

=

AE

AC

AD

AB

−1=

AE

AC

−1

AD

BD

=

AE

CE

EC=1×

1.5

3

=2 cm

Step-by-step explanation:Mark me as brainlist

Step-by-step explanation:The given information is shown in the attached diagram.

DE∣∣BC

⟹∠ADE=∠ABC Corresponding angles

∠AED=∠ACB Corresponding angles

∠A is common to both the triangles.

∴ΔADE∼ΔABC by AAA similarity

⟹

AD

AB

=

AE

AC

AD

AB

−1=

AE

AC

−1

AD

BD

=

AE

CE

EC=1×

1.5

3

=2 cm