In trapeziumif distance between parallel sidesis 13 cm andlengthsof parallel sidesis& 6cmand 11cm. Then find itsarea. About the author Cora
Step-by-step explanation: Area if trapezium=1/2 × (a+b) × height Area if trapezium=1/2 × (a+b) × height 1/2× (6+11) ×13 Area if trapezium=1/2 × (a+b) × height 1/2× (6+11) ×13= 1/2×17 ×13 Area if trapezium=1/2 × (a+b) × height 1/2× (6+11) ×13= 1/2×17 ×13=1/2×221 Area if trapezium=1/2 × (a+b) × height 1/2× (6+11) ×13= 1/2×17 ×13=1/2×221 =110.5 Area if trapezium=1/2 × (a+b) × height 1/2× (6+11) ×13= 1/2×17 ×13=1/2×221 =110.5so, area of trapezium =110.5 Reply
Answer: 110.5 Step-by-step explanation: h= 13 length of parallel sides = 6cm and 11 cm Area of trapazium = 1/2 × ( sum of parallel sides) × h 1/2 × ( 11+6) × 13 1/2 × 17 ×13 = 110.5 Reply
Step-by-step explanation:
Area if trapezium=1/2 × (a+b) × height
Area if trapezium=1/2 × (a+b) × height 1/2× (6+11) ×13
Area if trapezium=1/2 × (a+b) × height 1/2× (6+11) ×13= 1/2×17 ×13
Area if trapezium=1/2 × (a+b) × height 1/2× (6+11) ×13= 1/2×17 ×13=1/2×221
Area if trapezium=1/2 × (a+b) × height 1/2× (6+11) ×13= 1/2×17 ×13=1/2×221 =110.5
Area if trapezium=1/2 × (a+b) × height 1/2× (6+11) ×13= 1/2×17 ×13=1/2×221 =110.5so, area of trapezium =110.5
Answer:
110.5
Step-by-step explanation:
h= 13
length of parallel sides = 6cm and 11 cm
Area of trapazium = 1/2 × ( sum of parallel sides) × h
1/2 × ( 11+6) × 13
1/2 × 17 ×13
= 110.5