In the given figure , O is the centre of the circle and ACB is inscribed in arc ACB. If ACB = 650 , then find m(arcAPB). About the author Margaret
一═デ︻ αηѕωєя ︻デ═一 m(arc ACB)=230° Explanation: Given : ∠ACB is inscribed in a arc ACB of a circle with centre O. ∠ACB =65° The Inscribed Angle Theorem : The measure of an inscribed angle is half the measure the arc intercepted by it. Therefore , ∠ACB= half of Measure of arc AB ⇒Measure of arc AB = 2 x ∠ACB = 2 x 65° =130° Since arcAB is minor arc and arc ACb is major arc and tyhe sum of minor and major arc is 360°. ⇒ Measure of Major arc = 360°- Minor arc ⇒ Measure of arc ACB = 360° -130° =230° Hence, m(arc ACB) =230° Reply
一═デ︻ αηѕωєя ︻デ═一
m(arc ACB)=230°
Explanation:
Given : ∠ACB is inscribed in a arc ACB of a circle with centre O.
∠ACB =65°
The Inscribed Angle Theorem : The measure of an inscribed angle is half the measure the arc intercepted by it.
Therefore , ∠ACB= half of Measure of arc AB
⇒Measure of arc AB = 2 x ∠ACB = 2 x 65° =130°
Since arcAB is minor arc and arc ACb is major arc and tyhe sum of minor and major arc is 360°.
⇒ Measure of Major arc = 360°- Minor arc
⇒ Measure of arc ACB = 360° -130°
=230°
Hence, m(arc ACB) =230°