In swimming pool measuring 90 m X 40 m, 150 men take a dip. If the average displacement of water by a man is 8 m3 , then rise in water level is About the author Gianna

Given; Length of swimming pool= 90m=l Breadth of swimming pool= 40m=b Displacement of water by 1 man = 8 cu.m. To find; Increase in height when 150 men take a dip in the pool (h) Solution; According to Archimedes principle, Displacement of liquid = Total volume of body immersed in liquid. Displacement of liquid = Increase in volume = l × b × h = 40*90*h Volume of immersed body = Volume of 1 man * No. of men= 8*150 ∴ 40 * 90 * h = 8 * 150 3600 * h = 1200 h = 1200/3600 = 1/3 h = 0.333 m. Answer; The rise in water level will be by 0.333 m. Reply

Given;Length of swimming pool= 90m=l

Breadth of swimming pool= 40m=b

Displacement of water by 1 man = 8 cu.m.

To find;Increase in height when 150 men take a dip in the pool (h)

Solution;

According to Archimedes principle,

Displacement of liquid = Total volume of body immersed in liquid.

Displacement of liquid = Increase in volume = l × b × h = 40*90*h

Volume of immersed body = Volume of 1 man * No. of men= 8*150

Answer;

The rise in water level will be by

0.333 m.