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In swimming pool measuring 90 m X 40 m, 150 men take a dip. If the average displacement

of water by a man is 8 m3
By Gianna

In swimming pool measuring 90 m X 40 m, 150 men take a dip. If the average displacement

of water by a man is 8 m3

, then rise in water level is​

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Gianna

(3)
In the picture on the right, the angles between
the radii and the chords are equal.
Prove that the chords are o



If point M is the Midpoint of seg AB , l (BM) = 2.8 cm . Find l (AM) = _____________

a• 2.8 cm
b• 1.4

1 thought on “In swimming pool measuring 90 m X 40 m, 150 men take a dip. If the average displacement <br /><br /> of water by a man is 8 m3<br”

  1. Given;

    Length of swimming pool= 90m=l

    Breadth of swimming pool= 40m=b

    Displacement of water by 1 man = 8 cu.m.

    To find;

    Increase in height when 150 men take a dip in the pool (h)

    Solution;

    According to Archimedes principle,

    Displacement of liquid = Total volume of body immersed in liquid.

    Displacement of liquid = Increase in volume = l × b × h = 40*90*h

    Volume of immersed body = Volume of 1 man * No. of men= 8*150

    • ∴ 40 * 90 * h = 8 * 150
    • 3600 * h = 1200
    • h = 1200/3600 = 1/3
    • h = 0.333 m.

    Answer;

    The rise in water level will be by 0.333 m.

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