In standstill water a steam boat is accelerated 3 m per square from position of rest in an interval of 8 sec determine the distance travel by the boat within the interval About the author Samantha
Answer: [tex]use the equation \begin{gathered}s = ut \: + \frac{1a {t}^{2} }{2 } \\ s = \: 0(8) + \frac{1(3)( {8}^{2} )}{2} \\ s = \frac{192}{2} \\ s = 96 \\ \end{gathered}s=ut+21at2s=0(8)+21(3)(82)s=2192s=96 so the distance travelled by boat in 8 sec is 96 m [/tex] Step-by-step explanation: hi piyush how are you Reply
use the equation [tex]s = ut \: + \frac{1a {t}^{2} }{2 } \\ s = \: 0(8) + \frac{1(3)( {8}^{2} )}{2} \\ s = \frac{192}{2} \\ s = 96 \\ [/tex] so the distance travelled by boat in 8 sec is 96 m Reply
Answer:
[tex]use the equation
\begin{gathered}s = ut \: + \frac{1a {t}^{2} }{2 } \\ s = \: 0(8) + \frac{1(3)( {8}^{2} )}{2} \\ s = \frac{192}{2} \\ s = 96 \\ \end{gathered}s=ut+21at2s=0(8)+21(3)(82)s=2192s=96
so the distance travelled by boat in 8 sec is 96 m
[/tex]
Step-by-step explanation:
hi piyush how are you
use the equation
[tex]s = ut \: + \frac{1a {t}^{2} }{2 } \\ s = \: 0(8) + \frac{1(3)( {8}^{2} )}{2} \\ s = \frac{192}{2} \\ s = 96 \\ [/tex]
so the distance travelled by boat in 8 sec is 96 m