in parallelogram pqrs angle q=(4x-5) and angle s=(3x+5) calculate q and r​

2 thoughts on “in parallelogram pqrs angle q=(4x-5) and angle s=(3x+5) calculate q and r​”

1. Answer:

   In a parallelogram PQRS angle S=4x-5 and angle Q=2x-9. What is the value of angle Q and angle P?

   Then angle S is equal to angle Q by property of paralleogram so 4x-5=2x-9 and x comes out to be -2units the negative sign is removed as angle is a scalar quantity.

   Angle Q = -13 units and hence 13 units

   Angle p = 180 – Q (property of adjacent angles of paralleogram)

   P= 167 units.

   But if vertices are not taken in order then it may be possible that Q+S = 180 ( property of adjacent angle of parallelogram)

   So 4x-5 +2x-9 = 180 , x comes out to be 27.6

   So angle P is 133.8 and Q is 46.2 by the given equations

   Reply

2. Answer:

   S__________R

   | |

   | |

   | |

   |__________ |

   P q

   q = 4x – 5

   s = 3x + 10

   q and s are opposite Angles, So they are equal

   4x – 5 = 3x + 10

   4x – 3x = 10 + 5

   x = 15

   q = 4 (15) – 5

   60 – 5 = 55

   5 = 3x + 10

   45 + 10 = 55

   Sum of Adjacent angles is 180°

   Lq + LR = 180°

   55 + LR = 180°

   LR = 180° – 55

   LR = 125°

   Lq = 55°

   LR = 125°

   Explanation:

   ….I hope it helps you! !….

   Purple u Army

   Reply