In ∆ ABC , a = 2 , b = 3 and sin A = 2/3 then B is equal to * 30° 60° 90° 120 About the author Melody
[tex]\huge\bf\underline{\red{A}\green{N}\orange{S}\pink{W}\purple{E}\blue{R}}[/tex] In △ABC a=2,b=3 and sinA=2/3 By applying sine law sinAa=sinBb=sinCc →2/32=sinB3→sinB=1⇒B=2π. [tex]{\fcolorbox{blue}{black}{\orange{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: Itz \:Janvi \: Here\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}}}[/tex] Reply
[tex]\huge\bf\underline{\red{A}\green{N}\orange{S}\pink{W}\purple{E}\blue{R}}[/tex]
In △ABC a=2,b=3 and sinA=2/3
By applying sine law
sinAa=sinBb=sinCc
→2/32=sinB3→sinB=1⇒B=2π.
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