In how many years a sum of $50,000 becomes $57,245 at the rate of 7% compounded annually?mettiDivyarupa Support About the author Claire
Step-by-step explanation: Question:– In how many years,a sum of $50,000 becomes $57,245 at the rate of 7% compounded annually ? Answer:– Given :– • Principal is $50,000 • Amount is $57,245 • Rate is 7% To find :– Time taken by the above principal to convert into the given amount Process :– As we know that:- [tex]⇒Amount = P (1+ \frac{r}{100} {)}^{n} \\ \\ [/tex] Inserting the values in the formula:– [tex]⇒57,245 = 50,000 (1+ \frac{7}{100} {)}^{n} \\ \\ ⇒57,245 = 50,000 ( \frac{107}{100} {)}^{n} \\ \\ ⇒ \frac{57,245}{50,000} = (\frac{107}{100} {)}^{n} \\ \\ ⇒ \frac{11449}{10000} = (\frac{107}{100} {)}^{n} \\ \\ ⇒( \frac{107}{100} {)}^{2} = ( \frac{107}{100} {)}^{n} \\ \\ ⇒2 = n \\ \\ ⇒n = 2[/tex] ∴ The principal will become equal to amount after 2 years. ──────────────────────────── Hope it helps you… #Be brainly Reply
Step-by-step explanation:
Question:–
In how many years,a sum of $50,000 becomes $57,245 at the rate of 7% compounded annually ?
Answer:–
Given :–
• Principal is $50,000
• Amount is $57,245
• Rate is 7%
To find :–
Time taken by the above principal to convert into the given amount
Process :–
As we know that:-
[tex]⇒Amount = P (1+ \frac{r}{100} {)}^{n} \\ \\ [/tex]
Inserting the values in the formula:–
[tex]⇒57,245 = 50,000 (1+ \frac{7}{100} {)}^{n} \\ \\ ⇒57,245 = 50,000 ( \frac{107}{100} {)}^{n} \\ \\ ⇒ \frac{57,245}{50,000} = (\frac{107}{100} {)}^{n} \\ \\ ⇒ \frac{11449}{10000} = (\frac{107}{100} {)}^{n} \\ \\ ⇒( \frac{107}{100} {)}^{2} = ( \frac{107}{100} {)}^{n} \\ \\ ⇒2 = n \\ \\ ⇒n = 2[/tex]
∴ The principal will become equal to amount after 2 years.
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Hope it helps you…
#Be brainly