there are 12 horses competing for first place, 11 competing for second place (since one has already won first place), and 10 competing for third place (since two out of the 12 have won first and second places). Multiply the three to get the number of ways. This is a permutation. So you would do 12!/[(12-3)!]1
there are 12 horses competing for first place, 11 competing for second place (since one has already won first place), and 10 competing for third place (since two out of the 12 have won first and second places). Multiply the three to get the number of ways. This is a permutation. So you would do 12!/[(12-3)!]1
[tex]\begin{gathered}{\Huge{\textsf{\textbf{\underline{\underline{\purple{Answer:}}}}}}}\end{gathered}[/tex]
[tex]\implies[/tex]Example:-
there are 12 horses competing for first place, 11 competing for second place (since one has already won first place), and 10 competing for third place (since two out of the 12 have won first and second places). Multiply the three to get the number of ways. This is a permutation. So you would do 12!/[(12-3)!]1
Step-by-step explanation:
Example:-
there are 12 horses competing for first place, 11 competing for second place (since one has already won first place), and 10 competing for third place (since two out of the 12 have won first and second places). Multiply the three to get the number of ways. This is a permutation. So you would do 12!/[(12-3)!]1