In Fig. AB= AC and AD is the bisector of
ZBAC.
State three pairs of equal parts
in triangles ADB and ADC.
(ii)

In Fig. AB= AC and AD is the bisector of
ZBAC.
State three pairs of equal parts
in triangles ADB and ADC.
(ii): Is AADB AADC? Give
reasons
Is B= 2C? Give reasons.​

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1 thought on “In Fig. AB= AC and AD is the bisector of<br />ZBAC.<br />State three pairs of equal parts<br />in triangles ADB and ADC.<br />(ii)”

  1. Here in \Delta ADB and \Delta ADC.

    i) Three pair of equal parts are:

    AD = AD ( common side )

    BD = CD ( as d is the mid point of BC)

    AB = AC (given in the question)

    ii) Now,

    by SSS Congruency rule,

    \Delta ADB\cong \Delta ADC

    iii) As both triangles are congruent to each other we can compare them and say

    \angle B = \angle C.

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