In Fig. AB= AC and AD is the bisector of

ZBAC.

State three pairs of equal parts

in triangles ADB and ADC.

(ii): Is AADB AADC? Give

reasons

Is B= 2C? Give reasons.

# In Fig. AB= AC and AD is the bisector of

### 1 thought on “In Fig. AB= AC and AD is the bisector of<br />ZBAC.<br />State three pairs of equal parts<br />in triangles ADB and ADC.<br />(ii)”

### Leave a Comment

You must be logged in to post a comment.

Here in \Delta ADB and \Delta ADC.

i) Three pair of equal parts are:

AD = AD ( common side )

BD = CD ( as d is the mid point of BC)

AB = AC (given in the question)

ii) Now,

by SSS Congruency rule,

\Delta ADB\cong \Delta ADC

iii) As both triangles are congruent to each other we can compare them and say

\angle B = \angle C.