in cm) 145
150
155
160
tudent 6
10
15
12
raw a box graph to represent the data given above

1 thought on “in cm) 145<br />150<br />155<br />160<br />tudent 6<br />10<br />15<br />12<br />raw a box graph to represent the data given above”

1. Answer:

   If the data is arranged in an ordered list, and the number of data values, n, is odd then the

   n + 1

   2

   th value will be a single item from the list, and this will be the median. For example, if n = 95 the median will be the

   95 + 1

   2

   = 48th value. However, if n is even then

   n + 1

   2

   will determine the two central values that must be averaged to obtain the median. For example, if n = 156 then

   156 + 1

   2

   = 78.5, which tells us that we must average the 78th and 79th values to get the median.

   For large sets of data, we estimate the lower quartile, median and upper quartile using the

   n

   4

   th,

   n

   2

   th and

   3n

   4

   th values. For example, if n = 2000 , then we would estimate the lower quartile, median and upper quartile using the 500th, 1000th and 1500th values

   Step-by-step explanation:

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