In an arithemetic sequence 5th term 23 and 9th term is 39 find common difference and 14th term

Question

Adalynn · Answer

Answer:   59   Step-by-step explanation:   Let the first team be a ;  and the common difference be r;   therefore 2nd term = a + r = a{2} ;  a3= a+ 2r;  a4= a+3r;  a5= a+ 4r= 23;  a9 = a+8r = 39;  solving these two equations= r= 4; a= 23- 4r=23-16=7  therefore a14= a+ 13r= 7+ 13*4=7+52= 59

Arianna

the is the decimal number 7.9 read a)seven b)seventy six c)seven point six d)seven point hundred

2) The Ratio of two numbers is 7:2 and the greater number is 21. Find the smaller
number.

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