In an arithemetic sequence 3rd term 37 and 7th term is 73 find 30th term,

Question

Melanie · Answer

Answer:   A3=37,A7=73  a+2d=37,a+6d=73  on solving both equations  4d=36  d=9  substitute d=9 in a+2d=37  a+18=37  a=19  A30=a+29d  A30=19+29(9)  A30=19+261  A30=280

Arya

prove that

(1/1+√2) + (1/√2+√3) + (1/√3+√4) + (1/√4+√5) + (1/√5+√6) + (1/√6+√7) + (1/√7+√8) + (1/√8+√9)

the sum of two rational number is minus- 9 by 60 if one of the number is minus 7 by 12 find the other

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