In a two-digit natural number, the digit at the tens place is equal to the square of the digit at units place. If 18 is subtracted from the number, the digits get interchanged. Find the number. About the author Madeline
Step-by-step explanation: Let the number be 10x+y GIVEN: x=y² 10x+y-18=10y+x 9x-9y=18 x-y=2 -> x=2+y EQUATING BOTH THE EQUATIONS WE GET AS, 2+y=y² y²-y-2=0 (y-2)(y+1)=0 y=+2(as both the numbers are natural -1 is neglected) x=2²=4 SO THE NUMBER IS 10(4)+2 = 40+2=42 hope it is helpful if so please mark me as brainliest Reply
Step-by-step explanation:
Let the number be 10x+y
GIVEN:
EQUATING BOTH THE EQUATIONS WE GET AS,
2+y=y²
y²-y-2=0
(y-2)(y+1)=0
y=+2(as both the numbers are natural -1 is neglected)
x=2²=4
SO THE NUMBER IS 10(4)+2 = 40+2=42
hope it is helpful
if so please mark me as brainliest