In a team of 11 players, two players of ages 18 years and 20 years respectively are replaced with two new players. The average age of the 11 players exceeds with 2 months. What is the average age of two new players? About the author Sophia
Answer: Step-by-step explanation: Let the average age of 11 players be x. Then, total age of 11 players = 11x Total age of 9 players = 11x – (17 + 20) = 11x – 37 Let y be the total age of the 2 new players. Then 11 11x−37+y =x− 6 1 = 6 6x−1 ⇒66x−222+6y=66x−11 ⇒6y=−11+222=211y= 6 211 years ∴ Average of the two players = 2 y = 12 211 =17 years 7 months Reply
Answer:
Step-by-step explanation:
Let the average age of 11 players be x.
Then, total age of 11 players = 11x
Total age of 9 players = 11x – (17 + 20) = 11x – 37
Let y be the total age of the 2 new players.
Then
11
11x−37+y
=x−
6
1
=
6
6x−1
⇒66x−222+6y=66x−11
⇒6y=−11+222=211y=
6
211
years
∴ Average of the two players =
2
y
=
12
211
=17 years 7 months