In a right triangle RQP if PQ=5cm RQ=10cm find the value of :
(i) sin2P
(ii) tan R
(iii) sin P x cos P
(iv

In a right triangle RQP if PQ=5cm RQ=10cm find the value of :
(i) sin2P
(ii) tan R
(iii) sin P x cos P
(iv) sin2P – cos2 P

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  1. Step-by-step explanation:

    In △PQR, right angled at Q. If PQ=5 and RQ=10cm find sin

    2

    P.

    Medium

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    Answer

    PR

    2

    =PQ

    2

    +QR

    2

    PR

    2

    =25+100

    PR

    2

    =125

    PR=

    125

    =5

    5

    sin

    2

    P=

    PR

    2

    QR

    2

    =

    125

    100

    =

    5

    4

    solution

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