In a repeating decimal 0.1234512345…., What is the 2018th digit to the right of the decimal number? About the author Ayla
Step-by-step explanation: Given:– The repeating decimal is 0.1234512345… To find:– In a repeating decimal 0.1234512345…., What is the 2018th digit to the right of the decimal number? Solution:– Given decimal number = 0.1234512345… It is a non terminating recurring decimal The period of the number = 12345 Periodicity of the number = 5 The 2018th digit the right of the decimal =>2018 can be written as =>2015+3 2015 is a multiple of 5 so the pattern is completed . So ,2015 th digit = 5 2016th digit = 1 2017th digit = 2 2018 th digit = 3 (or) 2018/5 = 403.6 So the pattern would repeat 403 times. 2016th digit = 1 2017th digit = 2 2018 th digit = 3 Answer:– In a repeating decimal 0.1234512345…the 2018th digit to the right of the decimal number is 3 Reply
Step-by-step explanation:
Given:–
The repeating decimal is 0.1234512345…
To find:–
In a repeating decimal 0.1234512345…., What is the 2018th digit to the right of the decimal number?
Solution:–
Given decimal number = 0.1234512345…
It is a non terminating recurring decimal
The period of the number = 12345
Periodicity of the number = 5
The 2018th digit the right of the decimal
=>2018 can be written as
=>2015+3
2015 is a multiple of 5 so the pattern is completed .
So ,2015 th digit = 5
2016th digit = 1
2017th digit = 2
2018 th digit = 3
(or)
2018/5 = 403.6
So the pattern would repeat 403 times.
2016th digit = 1
2017th digit = 2
2018 th digit = 3
Answer:–
In a repeating decimal 0.1234512345…the 2018th digit to the right of the decimal number is 3