In a quadrilateral the angle are x°(x-10°),(X+30°),2x°. find the angle?​

2 thoughts on “In a quadrilateral the angle are x°(x-10°),(X+30°),2x°. find the angle?​”

1. Step-by-step explanation:

   Given that angles in the quadrilateral are

   x° (x-10°) (x+30°) and 2x°

   So, x+ x-10+ x+30+2x=360°

   5x + 20= 360

   5x = 360-20

   5x = 340

   x = 340/5

   x = 68°

   First angle = 68°.

   Second angle = x-10 = 68-10 = 58°.

   Third angle = x+ 30 = 68+30 = 98°.

   Fourth angle = 2x = 2× 68 = 136°.

   HOPE IT HELPS YOU MATE

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2. Step-by-step explanation:

   We know that sum of all angle of a quadrilateral is 360⁰

   x+x-10+x+30+2x=360⁰

   5x+20=360⁰

   5x=340⁰

   x=340/5=68⁰

   x=68⁰

   x-10= 68-10 =58⁰

   x+30=68+30 98⁰

   2x= 2×68 = 136⁰

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