In a parallelogram ABCD, if A = (3x – 8)° and∆D = (2x + 13)°, find the value of x and the measureof each angle of the parallelogram. About the author Genesis
Answer: 3x-8+2x+13 = 180 3x+2x-8+13 = 180 5x+5 = 130 5x = 125 x = 25 A = 3x-8 = 3 x 25 – 8 = 75-8 therefore A = 67° D = 2x + 13 = 2 x 25 + 13 = 50 + 13 = 63 therefore D = 63° therefore the angles are 67°,63°,67°,63°. Reply
Answer:
3x-8+2x+13 = 180
3x+2x-8+13 = 180
5x+5 = 130
5x = 125
x = 25
A = 3x-8
= 3 x 25 – 8
= 75-8
therefore A = 67°
D = 2x + 13
= 2 x 25 + 13
= 50 + 13
= 63
therefore D = 63°
therefore the angles are 67°,63°,67°,63°.
Answer:
x=37
Step-by-step explanation:
here A+D=180
and A=C,
B=D. because it’s parallelogram