In a bag, there are coins of 25 p, 10 p, and 5 p in the ratio of 1:2:3. If there is Rs. 30 in all, how many 5 pcoins are there? About the author Josie
Answer: There are 1500 coins of 5 p in the bag. Step-by-step-explanation: We have given that, There are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. Let the common multiple be x. ∴ 25 p coins = x 10 p coins = 2x 5p coins = 3x From the given condition, There are total Rs. 30 in the bag. Now, we know that, Re. 1 = 100 paise ⇒ Rs. 30 = 30 * 100 paise ⇒ Rs. 30 = 3000 paise ∴ x + 2x + 3x = 3000 ⇒ 3x + 3x = 3000 ⇒ 6x = 3000 ⇒ 3x = 1500 – – – [ Dividing by 2 ] ∴ There are 1500 coins of 5 p in the bag. Reply
Given :- In a bag, there are coins of 25 p, 10 p, and 5 p in the ratio of 1:2:3. If there is Rs. 30 in all To Find :- Number of 5 p coins Solution :- We know that 1 rupees = 100 paise 30 rupees = 30 × 100 = 3,000 paise Let Number of 25 paise = y Number of 10 paise = 2y Number of 5 paise = 3y y + 2y + 3y = 3000 6y = 3000 y = 3000/6 y = 500 [tex]\\[/tex] Reply
Answer:
There are 1500 coins of 5 p in the bag.
Step-by-step-explanation:
We have given that,
There are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3.
Let the common multiple be x.
∴ 25 p coins = x
10 p coins = 2x
5p coins = 3x
From the given condition,
There are total Rs. 30 in the bag.
Now, we know that,
Re. 1 = 100 paise
⇒ Rs. 30 = 30 * 100 paise
⇒ Rs. 30 = 3000 paise
∴ x + 2x + 3x = 3000
⇒ 3x + 3x = 3000
⇒ 6x = 3000
⇒ 3x = 1500 – – – [ Dividing by 2 ]
∴ There are 1500 coins of 5 p in the bag.
Given :-
In a bag, there are coins of 25 p, 10 p, and 5 p in the ratio of 1:2:3. If there is Rs. 30 in all
To Find :-
Number of 5 p coins
Solution :-
We know that
1 rupees = 100 paise
30 rupees = 30 × 100 = 3,000 paise
Let
Number of 25 paise = y
Number of 10 paise = 2y
Number of 5 paise = 3y
y + 2y + 3y = 3000
6y = 3000
y = 3000/6
y = 500
[tex]\\[/tex]