In 5.1g of a substance is added to 36g of water The vapour pressure of water decrease from 442mmofHg to 410mmofHg Find the molar mass of substance About the author Kennedy
Answer: Molar mass of substance = 32.67g Explanation: Vapour pressure of Pure water ([tex]P_{\°}[/tex]) = 442 torr Vapour of solution ([tex]P_{s}[/tex]) = 410 Weight of solute = 5.1g & weight of water = 36g => [tex]\frac{P_{\°}-P_{s}}{P_{s}} = \frac{n}{N}[/tex] (where n = moles of solute & N = moles of solvent) Let us consider the molar mass of solute as ‘x’ => [tex]\frac{442-410}{410}=(\frac{5.1}{x} )(\frac{18}{36} )[/tex] =>[tex]\frac{32}{410}=\frac{5.1}{2x}[/tex] => [tex]x=\frac{(5.1)(410)}{(2)(32)} = 32.67g[/tex] Hope you understood the answer 🙂 BTW Brainliest? Reply
Answer:
Molar mass of substance = 32.67g
Explanation:
Vapour pressure of Pure water ([tex]P_{\°}[/tex]) = 442 torr
Vapour of solution ([tex]P_{s}[/tex]) = 410
Weight of solute = 5.1g & weight of water = 36g
=> [tex]\frac{P_{\°}-P_{s}}{P_{s}} = \frac{n}{N}[/tex] (where n = moles of solute & N = moles of solvent)
Let us consider the molar mass of solute as ‘x’
=> [tex]\frac{442-410}{410}=(\frac{5.1}{x} )(\frac{18}{36} )[/tex]
=>[tex]\frac{32}{410}=\frac{5.1}{2x}[/tex]
=> [tex]x=\frac{(5.1)(410)}{(2)(32)} = 32.67g[/tex]
Hope you understood the answer 🙂
BTW Brainliest?