in 3 numbers the mean of the square of first 2 numbers is 26 and the mean of the square of the second and the first is 50 and the mean of the square of the third and the first number is 40 then what are the three numbers? About the author Josephine

Answer: Let the three numbers be x,y and z It is given x^2+y^2=26×2=52….(1) y^2+z^2=100….(2) z^2+x^2=80…(3) from ,(2) y^2=100-z^2 put this value of y^2 in (1) x^2+100-z^2=52 x^2-z^2=-48 Add this equation to (3) you will get 2x^2=32 which gives x=4 Put this value of x in equation (1) and (3) you will get y=6 and z=8 So the numbers are 4,6,8 Reply

Answer:Let the three numbers be x,y and z

It is given

x^2+y^2=26×2=52….(1)

y^2+z^2=100….(2)

z^2+x^2=80…(3)

from ,(2)

y^2=100-z^2

put this value of y^2 in (1)

x^2+100-z^2=52

x^2-z^2=-48

Add this equation to (3) you will get

2x^2=32 which gives x=4

Put this value of x in equation (1) and (3) you will get y=6 and z=8

So the numbers are 4,6,8

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