In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :

In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :

A) 19
B) 29
C) 39
D) 49

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Vivian

2 thoughts on “In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :<br /><br />”

  1. Given

    • In 10 years, A will be twice as old as B was 10 years ago.
    • A is now 9 years older than B.

    Explanation

    Let the present age of B be x years and present age of A be (x+9) years.

    ✮After 10 years,

    • Age of A = (x + 9 + 10) years

    ✮Before 10 years,

    • Age of B be = (x − 10) years

    ✮Now, We’ve to compare the both equations to find the desired results as:-

    [tex] \\ \colon\implies{\sf{ (x+9+10)=2(x−10)}} \\ \\ \\ \colon\implies{\sf{ x + 19 = 2x – 20 }} \\ \\ \\ \colon\implies{\sf{ 19 + 20 = 2x – x }} \\ \\ \\ \colon\implies{\sf{ x = 39 \ years}} \\ [/tex]

    Hence,

    [tex] \\ {\underline{\sf{ The \ present \ age \ of \ B \ is \ 39 \ years. }}} \bigstar \\ [/tex]

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