If two numbers have a sum of 12 and twice the first greater than four times the second, what are the numbers?

1 thought on “If two numbers have a sum of 12 and twice the first greater than four times the second, what are the numbers?”

1. Answer:

   x+y=-1

   2x+4y=-10

   Let’s start with the first:

   x+y=-1

   You can solve for x or y, it doesn’t matter.

   x=-1-y

   Now, plug this into the second equation:

   2(-1-y)+4y=-10

   Distribute:

   -2–2y+4y=-10

   Now simplify:

   -2+2y=-10

   2y=-8

   y=-4

   Now, plug this one into the first, as that will be easier to compute.

   x+y=-1

   x-4=-1

   x=3

   So, the first number, x, is 3, and the second number, y, is -4

   Step-by-step explanation:

   x+y=-1

   2x+4y=-10

   Let’s start with the first:

   x+y=-1

   You can solve for x or y, it doesn’t matter.

   x=-1-y

   Now, plug this into the second equation:

   2(-1-y)+4y=-10

   Distribute:

   -2–2y+4y=-10

   Now simplify:

   -2+2y=-10

   2y=-8

   y=-4

   Now, plug this one into the first, as that will be easier to compute.

   x+y=-1

   x-4=-1

   x=3

   So, the first number, x, is 3, and the second number, y, is -4

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