If two adjacent angles of a parallelogram ABCD are (5x-10) and (x+10), then find theratio of these angles.(3 About the author Maya
Step-by-step explanation: The adjacent angles of parallelogram are supplementary So the sum of adjacent angles = 180° 5x – 10 + x + 10 =180° 6x =180 x =180/6 x =30 5x-10 = 5(30) -10 = 150 -10 =140 x + 10 = 30 +10 =40 The ratio of these angles are given by 140 : 40 70 : 20 7 : 2 I HOPE THIS ANSWER WILL HELPS YOU. Reply
Answer: 7:2 is the ratio Step-by-step explanation: As it is given adjacent angles, (5x-10)+(x+10)=180 [in a parallelogram sum of adjacent angles=180] 6x=180 x=30 degrees The angles are 5(30)-10,30+10 i.e. 140,40 Ratio is 140:40=7:2 Reply
Step-by-step explanation:
The adjacent angles of parallelogram are supplementary
So the sum of adjacent angles = 180°
5x – 10 + x + 10 =180°
6x =180
x =180/6
x =30
5x-10 = 5(30) -10
= 150 -10
=140
x + 10 = 30 +10
=40
The ratio of these angles are given by
140 : 40
70 : 20
7 : 2
I HOPE THIS ANSWER WILL HELPS YOU.
Answer:
7:2 is the ratio
Step-by-step explanation:
As it is given adjacent angles,
(5x-10)+(x+10)=180 [in a parallelogram sum of adjacent angles=180]
6x=180
x=30 degrees
The angles are 5(30)-10,30+10
i.e. 140,40
Ratio is 140:40=7:2