IF THE ZEROS OF POLYNOMIAL
[tex] {x}^{3} – 3 {x}^{2} + x + 1[/tex]
ARE
[tex]a – b, \: a , \: a + b \: , \: [/te

2 thoughts on “IF THE ZEROS OF POLYNOMIAL <br />[tex] {x}^{3} – 3 {x}^{2} + x + 1[/tex]<br />ARE <br />[tex]a – b, \: a , \: a + b \: , \: [/te”

1. Answer:

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2. Step-by-step explanation:

   a−b,a,a+b are zeroes of x

   3

   −3x

   2

   +x+1

   ⇒a−b+a+a+b= sum of zeroes = 3

   ⇒3a=3

   ⇒a=1

   (a−b)(a)(a+b)= product of zeroes =−1

   ⇒(1−b)(1+b)=−1

   ⇒1−b

   2

   =−1

   ⇒b

   2

   =2

   ⇒b=±

   2

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