If the sum of the first n terms of an AP is given by Sn=(3n²-n), find its nth term. About the author Bella
Given Sum of n terms is S n =3n 2 −4n So Sum of n−1 terms is S n−1 =3(n−1) 2 −4(n−1) =3n 2 −6n+3−4n+4 =3n 2 −10n+7 Sum of n terms is equal to sum of n−1 terms plus n th term ⟹n th term =S n −S n−1 =3n 2 −4n−(3n 2 −10n+7) n th term=6n−7 Reply
Answer: An(nth term) is given by Sn – Sn-1 =>An=3n²-n-3n²-3-n+1 =>An=-2-2n answerr hope it’s help you plss mark me brainliest!!! Reply
Given Sum of n terms is S
n
=3n
2
−4n
So Sum of n−1 terms is S
n−1
=3(n−1)
2
−4(n−1)
=3n
2
−6n+3−4n+4
=3n
2
−10n+7
Sum of n terms is equal to sum of n−1 terms plus n
th
term
⟹n
th
term =S
n
−S
n−1
=3n
2
−4n−(3n
2
−10n+7)
n
th
term=6n−7
Answer:
An(nth term) is given by Sn – Sn-1
=>An=3n²-n-3n²-3-n+1
=>An=-2-2n answerr
hope it’s help you
plss mark me brainliest!!!