If the speed of a car is decreased by 8ʻkm/h, it takes 1 hour more to cover adistance of 240 km. Find the origi nal speed of the car.1 About the author Harper
Answer: Let the speed of car be xkmph Let it takes Time t hrs to cover the distance of 240km ⟹xt=240⋯(1) speed is decreased by 8⟹x−8 Time is increased by 1⟹t+1 it covers the same distance so (x−8)(t+1)=240 xt+x−8t−8=240 From (1)⟹x−8t−8=0 x=8t+8 Put it in (1)⟹(8t+8)(t)=240 t 2 +t−30=0 t 2 +6t−5t−30=0 t(t+6)−5(t+6)=0 (t−5)(t+6)=0 t=5,−6 Time cannot be negative so t=5 Put it in (1) ⟹x(5)=240⟹x=12kmph Reply
Answer: the speed of car be xkmph Let it takes Time t hrs to cover the distance of 240km =xt=240.(1) speed is decreased by 8 x-8 Time is increased by 13t+1 it covers the same distance so (x-8)(t+1)3240 xt+x-8t-83240 From (1)-x-8t-8=D0 x=8t+8 Put it in (1)(8t+8)(t)=240 t 2 +t-30=0 t 2 +6t-5t-30=0 t(t+6)-5(t+6)=0 (t-5)(t+6)=0 t35,-6 Time cannot be negative so t=5 Put it in (1) =>X(5)=240—x=12kmph Step-by-step explanation: pls mark brainliest Reply
Answer:
Let the speed of car be xkmph
Let it takes Time t hrs to cover the distance of 240km
⟹xt=240⋯(1)
speed is decreased by 8⟹x−8
Time is increased by 1⟹t+1
it covers the same distance so (x−8)(t+1)=240
xt+x−8t−8=240
From (1)⟹x−8t−8=0
x=8t+8
Put it in (1)⟹(8t+8)(t)=240
t
2
+t−30=0
t
2
+6t−5t−30=0
t(t+6)−5(t+6)=0
(t−5)(t+6)=0
t=5,−6
Time cannot be negative so t=5
Put it in (1)
⟹x(5)=240⟹x=12kmph
Answer:
the speed of car be xkmph
Let it takes Time t hrs to cover the distance of
240km
=xt=240.(1)
speed is decreased by 8 x-8
Time is increased by 13t+1
it covers the same distance so (x-8)(t+1)3240
xt+x-8t-83240
From (1)-x-8t-8=D0
x=8t+8
Put it in (1)(8t+8)(t)=240
t
2
+t-30=0
t
2
+6t-5t-30=0
t(t+6)-5(t+6)=0
(t-5)(t+6)=0
t35,-6
Time cannot be negative so t=5
Put it in (1)
=>X(5)=240—x=12kmph
Step-by-step explanation:
pls mark brainliest