If the speed of a car is decreased by 12 km/h, it takes 1 hour more to cover adistance of 240 km. Find the original speed of the car. About the author Brielle

Answer: Step-by-step explanation: Let the speed of the car be x km per hour Distance = 240 km Speed of car = x km per hour Time = Distance/speed Time = 240/x If the speed of the car is decreased by 8 km per hour, it takes 1 hour more to cover a distance of 240 km Time during changed speed = 240 km /x – 8 km per hour 240/(x – 8) – 240/x = 1 hour 240x —240 (x – 8)/ x (x – 8) = 1 hour 240x — 240x + 1920/ x^2 – 8x = 1 hour 1920/x^2 – 8x = 1 hour Cross multiplication x^2 – 8x = 1920 x^2 – 8x -1920 = 0 x^2 – 48x + 40 x – 1920 x (x – 48) + 40 (x – 48) (x + 40) (x – 48) x = —40 is not possible being negative hence discarded x = 48 km per hour The original speed of the car was 48 km per hour Reply

Answer:Step-by-step explanation:Let the speed of the car be x km per hour

Distance = 240 km

Speed of car = x km per hour

Time = Distance/speed

Time = 240/x

If the speed of the car is decreased by 8 km per hour, it takes 1 hour more to cover a distance of 240 km

Time during changed speed

= 240 km /x – 8 km per hour

240/(x – 8) – 240/x = 1 hour

240x —240 (x – 8)/ x (x – 8) = 1 hour

240x — 240x + 1920/ x^2 – 8x = 1 hour

1920/x^2 – 8x = 1 hour

Cross multiplication

x^2 – 8x = 1920

x^2 – 8x -1920 = 0

x^2 – 48x + 40 x – 1920

x (x – 48) + 40 (x – 48)

(x + 40) (x – 48)

x = —40 is not possible being negative hence discarded

x = 48 km per hour

The original speed of the car was 48 km per hour