If the specific heat of ice is 0.5 calories per gram degree Celsius, find the value in SI

system?​

1 thought on “If the specific heat of ice is 0.5 calories per gram degree Celsius, find the value in SI <br /><br />system?​”

1. Answer:

   Explanation:

   The problem provides you with the specific heat of ice, which is said to be equal to

   c

   ice

   =

   0.5 cal g

   −

   1

   ∘

   C

   −

   1

   =

   0.5

   a

   cal

   g

   ∘

   C

   As you can see, specific heat is expressed in units of energy, in this case calories, per gram Celsius, which means that a substance’s specific heat tells you how much energy is needed to increase the temperature of

   1 g

   of said substance by

   1

   ∘

   C

   .

   For ice, you know that if you provide

   0.5

   calories of heat to

   1 g

   of ice you will increase its temperature by

   1

   ∘

   C

   .

   This is how much heat you need to supply to a given sample of ice for every gram and for every

   1

   ∘

   C

   increase in temperature.

   To increase the temperature of

   20 g

   of ice by

   1

   ∘

   C

   , you need to provide it with

   0.5 cal

   for every gram. This will cause its temperature to increase by

   1

   ∘

   C

   .

   20

   g

   ⋅

   0.5 cal

   ∘

   C

   −

   1

   1

   g

   =

   10 cal

   ∘

   C

   −

   1

   For a

   1

   ∘

   C

   increase in temperature, you have

   1

   ∘

   C

   ⋅

   10 cal

   1

   ∘

   C

   =

   ∣

   ∣

   ∣

   ∣

   ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

   a

   a

   10 cal

   a

   a

   ∣

   ∣

   −−−−−−−−−

   As you can see, to increase the temperature of this sample by more than

   1

   ∘

   C

   you need to provide it with

   10 cal

   of heat for every

   1

   ∘

   C

   increase in temperature.

   For example, to increase the temperature of

   20 g

   of ice by

   3

   ∘

   C

   , you need to provide it with

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