If the side of the triang reilar field on the ratioof 2:3:4. if its perimeter is 900cm. find its area. About the author Amaya
Step-by-step explanation: a [tex] = (a = 2x )+ (b = 3x )+(c = 4x) (p = 900cm)[/tex] [tex]p = ab + bc + ca [/tex] [tex]900 + 2 + 3 + 4[/tex] [tex]900 = 9x \div 900[/tex] [tex]x = 900 \div 9[/tex] [tex]x = 100[/tex] [tex]ab = a = 2x = 2 \times 100[/tex] therefore [tex]a = 200cm[/tex] [tex]bc = b = 3x = 3 \times 100[/tex] [tex]therefore a = 300cm[/tex] [tex]ca = c = 4x = 4 \times 100[/tex] [tex]therefore = c = 400cm[/tex] s(s-a)( s-b)(s-c) 450(450–200) (450–300)(450–400) 450*225*75*150 5*3*2*5*3*5*3*5* 33750cm Reply
Step-by-step explanation: Let the common multiple be x 3x+5x+4x=900 12x=900 x=75 3x=75*3=225 5x=75*5=375 4x=75*4=300 Area, S=225+375+300/2 =450 Area=√450(450-225)(450-375)(450-300) =√450*225*75*150 =5*3*2*5*3*5*3*5 =33750cm Reply
Step-by-step explanation:
a
[tex] = (a = 2x )+ (b = 3x )+(c = 4x) (p = 900cm)[/tex]
[tex]p = ab + bc + ca [/tex]
[tex]900 + 2 + 3 + 4[/tex]
[tex]900 = 9x \div 900[/tex]
[tex]x = 900 \div 9[/tex]
[tex]x = 100[/tex]
[tex]ab = a = 2x = 2 \times 100[/tex]
therefore
[tex]a = 200cm[/tex]
[tex]bc = b = 3x = 3 \times 100[/tex]
[tex]therefore a = 300cm[/tex]
[tex]ca = c = 4x = 4 \times 100[/tex]
[tex]therefore = c = 400cm[/tex]
s(s-a)( s-b)(s-c)
450(450–200) (450–300)(450–400)
450*225*75*150
5*3*2*5*3*5*3*5*
33750cm
Step-by-step explanation:
Let the common multiple be x
3x+5x+4x=900
12x=900
x=75
3x=75*3=225
5x=75*5=375
4x=75*4=300
Area,
S=225+375+300/2
=450
Area=√450(450-225)(450-375)(450-300)
=√450*225*75*150
=5*3*2*5*3*5*3*5
=33750cm