if the roots of equations has real and equal than find value of m (m-12)x²+2(m-12)x+2=0 About the author Sadie
Answer: Step-by-step explanation: b^2-4ac=0 (2*(m-12))^2-4*(m*(m-12)*2)=0 4(m-12)^2-8m*(m-12)=0 4(m-12)^2=8m*(m-12) 4(m-12)=8m 4m-48=8m -4m=48 m=-12 Reply
Answer:
Step-by-step explanation:
b^2-4ac=0
(2*(m-12))^2-4*(m*(m-12)*2)=0
4(m-12)^2-8m*(m-12)=0
4(m-12)^2=8m*(m-12)
4(m-12)=8m
4m-48=8m
-4m=48
m=-12
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