Step-by-step explanation: Let α,β be the roots of ax2+bx+c=0 Then, αβ=ac and α+β=a−b Now it is given that, βα=nm Consider, nm+mn =βα+αβ =α.βα2+β2 =α.β(α+β)2−2α.β =aca2b2−ac =acb2−ac Reply
Step-by-step explanation:
Let α,β be the roots of ax2+bx+c=0
Then, αβ=ac and α+β=a−b
Now it is given that,
βα=nm
Consider,
nm+mn
=βα+αβ
=α.βα2+β2
=α.β(α+β)2−2α.β
=aca2b2−ac
=acb2−ac