If the perimeter of a square and a rectangle are equal, find which shape area is greater?? About the author Quinn

Answer: Perimeter Of square = Perimeter of Rectangle 4 × Side = 2(Length + Breadth) 4/2 × side= length + Breadth 2 × side = length + Breadth side = (length/ 2) + (Breadth/2) Area of square= Area of rectangle Side × side = length × Breadth (length/ 2 +Breadth/2) = length × Breadth So, the area of square is greater. Reply

Answer: ITS EASY Step-by-step explanation: If the perimeter of a square and a rectangle are equal, area of a square is greater than that of a rectangle. Perimeter of a square = perimeter of a rectangle. 3) So, 4*side = 2*(l+b). Reply

Answer:Perimeter Of square = Perimeter of Rectangle

4 × Side = 2(Length + Breadth)

4/2 × side= length + Breadth

2 × side = length + Breadth

side = (length/ 2) + (Breadth/2)

Area of square= Area of rectangle

Side × side = length × Breadth

(length/ 2 +Breadth/2) = length × Breadth

So, the area of square is greater.

Answer:ITS EASY

Step-by-step explanation:If the perimeter of a square and a rectangle are equal, area of a square is greater than that of a rectangle. Perimeter of a square = perimeter of a rectangle. 3) So, 4*side = 2*(l+b).