If the perimeter of a square and a rectangle are equal, find which shape area is greater?? About the author Quinn
Answer: Perimeter Of square = Perimeter of Rectangle 4 × Side = 2(Length + Breadth) 4/2 × side= length + Breadth 2 × side = length + Breadth side = (length/ 2) + (Breadth/2) Area of square= Area of rectangle Side × side = length × Breadth (length/ 2 +Breadth/2) = length × Breadth So, the area of square is greater. Reply
Answer: ITS EASY Step-by-step explanation: If the perimeter of a square and a rectangle are equal, area of a square is greater than that of a rectangle. Perimeter of a square = perimeter of a rectangle. 3) So, 4*side = 2*(l+b). Reply
Answer:
Perimeter Of square = Perimeter of Rectangle
4 × Side = 2(Length + Breadth)
4/2 × side= length + Breadth
2 × side = length + Breadth
side = (length/ 2) + (Breadth/2)
Area of square= Area of rectangle
Side × side = length × Breadth
(length/ 2 +Breadth/2) = length × Breadth
So, the area of square is greater.
Answer:
ITS EASY
Step-by-step explanation:
If the perimeter of a square and a rectangle are equal, area of a square is greater than that of a rectangle. Perimeter of a square = perimeter of a rectangle. 3) So, 4*side = 2*(l+b).