If the line segment joining (2,3) and (-1,2) isdivided internally in the ratio 3:4 by thegraph of the equation x+2y =k, then thevalue of k is About the author Rose
Answer: If the line segment joining (x 1 ,y 1 ) and (x 2 ,y 2 ) is divide by internally in the ratio m 1 :m 2 then the intersection point is x= m 1 +m 2 m 1 x 2 +m 2 x 1 and y= m 1 +m 2 m 1 y 2 +m 2 y 1 so x= 3+4 3×(−1)+4×2 = 7 5 y= 3+4 3×(2)+4×3 = 7 18 this point ( 7 5 , 7 18 ) lies on given equation of line. satisfying the equation 7 5 +2× 7 18 =k k= 7 41 Reply
Answer:
If the line segment joining (x
1
,y
1
) and (x
2
,y
2
) is divide by internally in the ratio m
1
:m
2
then the intersection point is
x=
m
1
+m
2
m
1
x
2
+m
2
x
1
and
y=
m
1
+m
2
m
1
y
2
+m
2
y
1
so
x=
3+4
3×(−1)+4×2
=
7
5
y=
3+4
3×(2)+4×3
=
7
18
this point (
7
5
,
7
18
) lies on given equation of line.
satisfying the equation
7
5
+2×
7
18
=k
k=
7
41
Step-by-step explanation
Ans :– K = 41/7