if the equation x2+2(k+2)+9k=0 has equal roots find the value of k​

1 thought on “if the equation x2+2(k+2)+9k=0 has equal roots find the value of k​”

1. Step-by-step explanation:

   if eq. has equal root then,

   D=0

   b²-4ac=0

   {2(k+2)}²-4×1×9k=0

   4(k²+4k+4)-36k=0

   4k²+16k+16-36k=0

   4k²-20k+16=0

   4(k²-5k+4)=0

   k²-5k+4=0

   k²-4k-k+4=0

   k(k-4)-1(k-4)=0

   (k-1)(k-4)=0

   either k-1=0 or k-4=0

   k-1=0 k-4=0

   k=1 k=4

   hence k=1 or 4

   #666

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