If the base of a triangle is 8.6 cm and height is 4.5 cm ,what is its Area? About the author Kinsley
Step-by-step explanation: Question:– If the base of the triangle is 8.6cm and height is 4.5cm,what is it’s area ? Answer:– Given :– • The given figure is a triangle. • The base of the triangle is 8.6cm. • The height of the triangle is 4.5cm. To find :– Area of the triangle Process :– As we all know that:- [tex]⇒Area \: of \: triangle \: = \frac{1}{2} \times Base \times Height \\ \\ [/tex] Inserting the above value in the formula:– [tex]⇒Area = \frac{1}{2} × Base × Height \\ \\ ⇒Area = \frac{1}{2} \times 8.6 \times 4.5 \\ \\ ⇒Area = \frac{1}{2} \times \frac{86}{10} \times \frac{45}{10} \\ \\ ⇒Area = 19.35cm²[/tex] Therefore,the area of the triangle is 19.35cm². ───────────────── ★ More to know Some more formulas:– [tex]• \: Area \: of \:scalene \: triangle = \frac{1}{2} × Base × Height \\ \\ • \: Perimeter \: of \: scalene \: triangle = a+b+c \\ \\ • \: Area \: of \: equilateral\: triangle = \frac{ \sqrt{3} }{4} × {Side}^{2} \\ \\ • \: Perimeter \: of \: isosceles \: triangle = 2a+b \\ \\ • \: Perimeter \: of \: equilateral \: triangle = 3× Side \\ \\ • \: Area \: of \: isosceles \: triangle = \frac{b {h}^{b} }{2} [/tex] ───────────────────────────── Hope it helps you… #Be brainly Reply
Given : Base of triangle is 8.6 cm. Height is 4.5 cm. To find : Area Solution : [tex] \boxed{\pmb{\tt Area \: of \: triangle = \dfrac{1}{2} \times base \times height}} [/tex] [tex] \tt \leadsto \dfrac{1}{2} \times 8.6 \times 4.5 [/tex] [tex] \tt \leadsto \dfrac{38.7}{2} [/tex] [tex] \tt \leadsto 19.35 [/tex] [tex] \bold{\therefore Area \: of \: triangle \: is \: 19.35 cm^{2}} [/tex] Reply
Step-by-step explanation:
Question:–
If the base of the triangle is 8.6cm and height is 4.5cm,what is it’s area ?
Answer:–
Given :–
• The given figure is a triangle.
• The base of the triangle is 8.6cm.
• The height of the triangle is 4.5cm.
To find :–
Area of the triangle
Process :–
As we all know that:-
[tex]⇒Area \: of \: triangle \: = \frac{1}{2} \times Base \times Height \\ \\ [/tex]
Inserting the above value in the formula:–
[tex]⇒Area = \frac{1}{2} × Base × Height \\ \\ ⇒Area = \frac{1}{2} \times 8.6 \times 4.5 \\ \\ ⇒Area = \frac{1}{2} \times \frac{86}{10} \times \frac{45}{10} \\ \\ ⇒Area = 19.35cm²[/tex]
Therefore,the area of the triangle is 19.35cm².
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★ More to know
Some more formulas:–
[tex]• \: Area \: of \:scalene \: triangle = \frac{1}{2} × Base × Height \\ \\ • \: Perimeter \: of \: scalene \: triangle = a+b+c \\ \\ • \: Area \: of \: equilateral\: triangle = \frac{ \sqrt{3} }{4} × {Side}^{2} \\ \\ • \: Perimeter \: of \: isosceles \: triangle = 2a+b \\ \\ • \: Perimeter \: of \: equilateral \: triangle = 3× Side \\ \\ • \: Area \: of \: isosceles \: triangle = \frac{b {h}^{b} }{2} [/tex]
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Hope it helps you…
#Be brainly
Given :
To find :
Solution :
[tex] \boxed{\pmb{\tt Area \: of \: triangle = \dfrac{1}{2} \times base \times height}} [/tex]
[tex] \tt \leadsto \dfrac{1}{2} \times 8.6 \times 4.5 [/tex]
[tex] \tt \leadsto \dfrac{38.7}{2} [/tex]
[tex] \tt \leadsto 19.35 [/tex]
[tex] \bold{\therefore Area \: of \: triangle \: is \: 19.35 cm^{2}} [/tex]