If the angle between vectors with magnitude 12 and 4 is 60% than their scalar product is

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1. Answer:

   1 is the answers it’s explanation is down below

   Explanation:

   Given, both vectors have same magnitude i.e., ∣a∣=∣b∣ and scalar product of vectors, a⋅b=

   2

   1

   (given).

   Let θ be the angle between two vectors a and b. Then,

   cosθ=

   ∣a∣∣b∣/a⋅b

   ⇒cos60

   ∘

   =

   ∣a∣∣a∣/2/1

   [∵∣a∣=∣b∣(given)]

   ⇒

   2/1

   =

   2∣a∣/2/1

   ⇒∣a∣=1

   ∴∣a∣=∣a∣=1.

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