if sec^2 theta (1 + sin theta) (1 – sin theta) =
a. cos theta
b. 1/cos theta
c. 1
d. 1/sin theta​

2 thoughts on “if sec^2 theta (1 + sin theta) (1 – sin theta) =<br />a. cos theta<br />b. 1/cos theta<br />c. 1<br />d. 1/sin theta​”

1. Answer:

   (sec^2 theta) (1 – sin^2 theta)

   (sec^2 theta) (cos^2 theta)

   (sec^2 theta) (1/sec^2 theta)

   = 1

   Reply

2. Answer:

   answer is 1

   [tex] { \sec(theta) }^{2} (1 + \sin(theta))(1 – \sin(theta)) = \frac{1}{ { \cos(theta) }^{2} } \times (1 – { \sin(theta) }^{2}) \\ \frac{1}{ { \cos(theta) }^{2} } \times { \cos(theta) }^{2} = 1[/tex]

   Step-by-step explanation:

   HOPEFULLY YOU LIKE THE ANSWER

   Reply