If p + q +r = 2, p2 + q? + r 2 = 30 and pqr = = = 10, then the value of (1 – p) (1 – 0)(1 – r) will
be

Options:

November 29, 2021

By Lyla

2 thoughts on “If p + q +r = 2, p2 + q? + r 2 = 30 and pqr = = = 10, then the value of (1 – p) (1 – 0)(1 – r) will<br />be<br /><br />Options:<br”

1. Answer:

   I think so this will be solution.

   Step-by-step explanation:

   Correct option is

   B

   qr=p

   2

   +

   a

   c

   As a(p+q)

   2

   +2bpq+c=0 and a(p+r)

   2

   +2bpr+c=0

   Then q,r are roots of

   a(p+x)

   2

   +2bpx+c=0

   ⇒ap

   2

   +ax

   2

   +2pax+2bpx+c=0

   ⇒ax

   2

   +(2pa+2pb)x+c+ap

   2

   =0

   Hence, product of roots is

   qr=

   a

   c+ap

   2

   ⇒qr=p

   2

   +

   a

   c

   Reply

2. p:q = r:s => p/q = r/s . Squaring both sides

   p^2/q^2 = r^2/s^2

   => (p^2+q^2)/q^2 = (r^2+s^2)/s^2

   => (p^2+q^2)/(r^2+s^2) = q^2/s^2 ……(1)

   p/q = r/s. Multiplying both sides with qs

   => pqs/q = rqs/s => pq(s/q)= rs (q/s)

   => pq/rs = (q/s)/(s/q)

   => pq/rs = q^2/s^2. Using this in (1) we get

   (p^2+q^2)/(r^2+s^2) = q^2/s^2 = pq/rs.

   Reply