If P (A’) = 0.7, P(B) =0.7,P(BIA) =0.5.then P(AUB) IS …. *O0.15O 0.10O 0.85O1 About the author Melanie
Answer: most appropriate ans 0.85 Step-by-step explanation: p(A) +P(B) -p(AnB) =p(AUB) p(A) = 1-P(A) = 1-0.7 = 0.3 p(B) = p(B/A) +p(AnB) 0.7 = 0.5 +p(AnB) 0.2= p(AnB) p(AUB) = 0.3+0.7-0.2 = 0.8 ≈0.85 Reply
Answer:
most appropriate ans 0.85
Step-by-step explanation:
p(A) +P(B) -p(AnB) =p(AUB)
p(A) = 1-P(A) = 1-0.7 = 0.3
p(B) = p(B/A) +p(AnB)
0.7 = 0.5 +p(AnB)
0.2= p(AnB)
p(AUB) = 0.3+0.7-0.2
= 0.8
≈0.85