. If p(x)= x³+ 3x²- 2x +4, then
find the value of p(2) + p(-2) – p(0)​

[tex]{Solution}[/tex]

Given:-

p(x) = x³ + 3x² – 2x + 4

To find :-

Value of p(2) + p(-2) -p(0)

SOLUTION:-

First Lets find p(2) that means we have to substitute x = 2

p(2) = x³ + 3x² – 2x + 4

p(2) = (2)³ +3(2)² -2(2) + 4

p(2) = 8 + 3(4) -4 + 4

p(2) = 8 + 12 – 4 + 4

p(2) = 20

Now for finding p(-2) that means we have to substitute x= -2

p(-2) = x³ + 3x² -2x + 4

p(-2) = (-2)³ +3(-2)² -2(-2)+4

p(-2) = -8 + 3(4) +4 +4

p(-2) = -8 + 12 + 8

p(-2) = 12

Now for finding p(0) that means we have to substitute x=0

p(0) = x³ + 3x² -2x + 4

p(0) = (0)³ + 3(0)² -2(0) + 4

p(0) = 0+0 +0 +4

p(0) = 4

Now we need p(2) + p(-2) + p(0)

= 20 + 12 + 4

= 36

So, the value of p(2) + p(-2) – p(0) is 36