if p(x) = 2x cube – x square + 3x +1 , find the value of p(-1) + p(1) – p(2)​

2 thoughts on “if p(x) = 2x cube – x square + 3x +1 , find the value of p(-1) + p(1) – p(2)​”

1. 2x^3-x^2+3x+1
   p(x)
   i)p(-1)=2(-1)^3-(-1)^2+3(-1)+1
   =2*-1-1+(-3)+1
   =-2-1-3+1
   =-5
   ii)p(1)=2(1)^3-(1)^2+3*1+1
   =2*1-1+3+1
   =2-1+3+1
   =5
   iii)p(2)=2(2)^3-(2)^2+3*2+1
   =2*8-4+6+1
   =16-4+6+1
   =19
   So, p(-1)+p(1)-p(2)
   =-5+5-19
   =-19 Ans.
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2. p(x)=2x³-x²+3x+1

   p(-1)=2(-1)³-(-1)²+3(-1)+1

   =-2-1-3+1

   = -5

   p(1)=2(1)³-(1)²+3(1)+1

   =2-1+3+1

   =5

   p(2)=2(2)³-(2)²+3(2)+1

   =16-4+6+1

   =19

   p(-1)+p(1)-p(2)

   -5+5+19

   =19

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