If one of the zeroes of polynomial x3-7x+6 is 2 , find the product of other 2 zeroes

If one of the zeroes of polynomial x3-7x+6 is 2 , find the product of other 2 zeroes

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  1. Answer:

    -3

    Step-by-step explanation:

    Product of roots of cubic polynomial of form ax³+bx²+cx+d is -d/a

    Here d is 6 , a is 1

    So product of all 3 roots is -6

    given that one zero is 2

    So product of other 2 zeroes is -6/2 = -3

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