If n(A-B)= 18, n(A ∪ B)= 70 and n(A ∩ B) = 25 then find n(B).​

2 thoughts on “If n(A-B)= 18, n(A ∪ B)= 70 and n(A ∩ B) = 25 then find n(B).​”

1. Answer:

   n(AuB) = n(A) + n (B) -n(AnB) —————-(1)

   We have n(AnB) = 25 and n(A-B) = 18

   With these 2 we can calculate n(A)

   n(A-B) = n(A) – n(AnB)

   18 = n(A) – 25

   => n(A) = 18 + 25 = 43

   now to calculate n(B) we can substitute all the values in equation 1

   70 = 43+ n(B) – 25

   70 = n(B) + 18

   n(B) = 70–18 = 52

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2. Answer:

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   Step-by-step explanation:

   We have n(AnB) = 25 and n(A-B) = 18

   With these 2 we can calculate n(A)

   n(A-B) = n(A) – n(AnB)

   18 = n(A) – 25

   => n(A) = 18 + 25 = 43

   now to calculate n(B) we can substitute all the values in equation 1

   70 = 43+ n(B) – 25

   70 = n(B) + 18

   n(B) = 70–18 = 52

   Reply