If lenght of a diagonal of a rhombus is 30cm nd its area is 240sqcm,Find its perimeter.

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Answer:34cm.

Step-by-step explanation:Let the length of other diagonal of the rhombus be x.

Area of the rhombus = 1/2(product of diagonals)

=> 240cm² = 1/2(30×x)

=> 240cm² = 30x/2

=> 240cm² = 15x

=> x = 240cm²/15

=> x = 16cm.

Now,

[tex] perimeter \: of \: rhombus \: \\ = > \sqrt{( {d1})^{2} + ( {d2})^{2} } [/tex]

[tex] = > \sqrt{( {16})^{2} + ( {30})^{2} } \\ = > \sqrt{256 + 900} \: \: \: \: \: \: \: \\ = > \sqrt{1156} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = > 34cm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

Hope it helps you.